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6b^2-6b-72=0
a = 6; b = -6; c = -72;
Δ = b2-4ac
Δ = -62-4·6·(-72)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-42}{2*6}=\frac{-36}{12} =-3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+42}{2*6}=\frac{48}{12} =4 $
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